Consider an archer shooting an arrow such that it follows a projectile trajectory. Recall that the range of a projectile depends on the square of the initial speed and the sin2θ. Now, sin2θ has a maximum value of 1, when theta equals 45°. In this case, the range of the projectile would be maximum for the given initial velocity. Consider two arrows launched at angles 30 and 60°, having the same initial velocity of 50 meters per second. The acceleration due to gravity for both the arrows is 9.8 meters per second squared. Therefore, substituting the velocity and angle values, the range covered by both the arrows equals 220.9 meters. Here, since sin(180 − sin2θ) is equal to 2θ, the range of the projectile for complementary launch angles is the same. However, the maximum height each arrow attains is proportional to the square of the initial velocity and sin2θ. Therefore, the maximum height is different for both cases.