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12.16:

Aldehydes and Ketones with HCN: Cyanohydrin Formation Mechanism

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Organic Chemistry
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JoVE Core Organic Chemistry
Aldehydes and Ketones with HCN: Cyanohydrin Formation Mechanism

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Cyanohydrin formation requires the generation of a strong base and a strong nucleophile, the cyanide anion, from HCN by using a catalytic amount of a base, or KCN. The base-catalyzed mechanism of cyanohydrin formation involves two steps: Nucleophilic  attack and proton transfer. In the first step, the cyanide anion attacks the carbonyl electrophile to give an addition intermediate—the alkoxide ion. Following this, the negatively charged oxygen atom on the intermediate abstracts a proton from HCN to give the addition product—the cyanohydrin—along with simultaneous regeneration of the cyanide catalyst.    Since the cyanide anion is also a good leaving group, the reaction can be reversed to give back the carbonyl compound. Treating the cyanohydrin with a strong base deprotonates the hydroxyl group to give an alkoxide anion, and subsequent loss of the cyanide ion forms the carbonyl compound.

12.16:

Aldehydes and Ketones with HCN: Cyanohydrin Formation Mechanism

Cyanohydrins are formed when cyanide nucleophiles and carbonyl compounds like aldehydes and ketones react. A strong base, the cyanide ion, catalyzes cyanohydrin formation. The ions are generated from HCN under aqueous conditions. Once the cyanide ions are generated, the first step involves the nucleophilic attack of the cyanide ions on the electrophilic carbonyl carbon. This attack shifts the π electrons from the C=O to the oxygen atom forming the alkoxide ion intermediate. The alkoxide anion thus formed is highly basic and abstracts a proton from another molecule of HCN to form cyanohydrin. This reaction also regenerates the cyanide catalyst.

Figure1

The strongly basic cyanide ion also functions as a good leaving group and can easily give back the aldehydes and ketones. In the presence of a strong base, the hydroxyl group on the cyanohydrin gets deprotonated to form the alkoxide anion. The alkoxide anion undergoes internal rearrangement of the delocalized electrons and loses the cyanide ion to form the carbonyl compound.

Figure2